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ThermoLab · Chapter 5

Control volumes and the first law

Solves steady-flow equipment using enthalpy, velocity, elevation, heat and work.

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TLCalculation engine · Base SI
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Engineering results

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Detailed calculation reportEquations · substitution · verification

Run the calculation to generate the report.

Engineering directory

13 linked modules on a single calculation base

Open any tool without losing your chosen unit system. Each page works on its own and keeps its navigation, report and export.

Engineering framework

Theory, equations and conditions of use

At steady state the stored energy does not change. The balance relates heat and work to enthalpy, kinetic energy and potential energy.

Fundamento

Conservation of mass

For one inlet and one outlet with no accumulation, the flow rates are equal.

\(\dot m_{in}=\dot m_{out}\)

Fundamento

Flow energy

Enthalpy combines internal energy and flow work.

\(q-w=\Delta h+\Delta ke+\Delta pe\)

Fundamento

Shaft power

With the positive sign taken outwards, a turbine produces work and a compressor consumes it.

\(\dot W=\dot Q-\dot m[(h_2-h_1)+(V_2^2-V_1^2)/2+g(z_2-z_1)]\)
Base documentalÇengel & Boles, 7th edition · SI appendices A-1 to A-28
USCS conversionA-1E to A-27E, via exact factors from the SI base
AlcancePreliminary design, teaching and independent verification

Engineering FAQ

Preguntas frecuentes

When can I neglect kinetic energy?+

When the change in V²/2 is small compared with the enthalpy change.

Does a valve conserve enthalpy?+

In the adiabatic model, with no work and negligible kinetic and potential changes, h₁≈h₂.

What sign convention does work use?+

Positive when it leaves the control volume.

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